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Mathematics, 01.07.2019 12:00 jose477

Write an equation in point-slope form for the line through the given point with the given slope. (10, –9); m = –2 y + 9 = –2(x – 10) y – 10 = –2(x + 9) y – 9 = –2(x + 10) y – 9 = –2(x – 10) 2. are the graphs of the lines in the pair parallel? explain. y = 6x + 9 27x – 3y = –81 no, since the slopes are different. yes, since the slopes are the same and the y-intercepts are different. no, since the y-intercepts are different. yes, since the slopes are the same and the y-intercepts are the same. write the equation of a line that is perpendicular to the given line and that passes through the given point. ; (–6, 5) are the graphs of the lines in the pair parallel? explain. y = x – 17 4x – 6y = –6 no, since the slopes are different. no, since the y-intercepts are different. yes, since the slopes are the same and the y-intercepts are the same. yes, since the slopes are the same and the y-intercepts are different. write the equation of a line that is perpendicular to the given line and that passes through the given point. 4x – 12y = 2; (10, –1) y = 3x + 29 y = x + 7 y = x + 29 y = –3x + 29 write the equation of a line that is perpendicular to the given line and that passes through the given point. 2x + 9y = –30; (–8, 0) y = x + 36 y = x + 36 y = x + 36 y = x – 8 write an equation in point-slope form for the line through the given point with the given slope. (–3, –7); m = y – 7 = (x + 3) y – 7 = (x – 3) y + 3 = (x + 7) y + 7 = (x + 3) are the graphs of the lines in the pair parallel? explain. y = 4x – 4 24x – 4y = 96 yes, since the slopes are the same and the y-intercepts are the same. no, since the y-intercepts are different. no, since the slopes are different. yes, since the slopes are the same and the y-intercepts are different. write the equation of a line that is perpendicular to the given line and that passes through the given point. –x + 5y = 14; (–5, –2) y = x – 27 y = 5x – 27 y = –5x – 27 y = x – 15 write an equation for the line that is parallel to the given line and that passes through the given point. y = –5x + 3; (–6, 3) y = –5x + 9 y = –5x + 27 y = 5x – 9 y = –5x – 27 write an equation in point-slope form for the line through the given point with the given slope. (8, –3); m = y – 8 = (x + 3) y – 3 = (x – 8) y – 3 = (x + 8) y + 3 = (x – 8) write an equation in point-slope form for the line through the given point with the given slope. (–10, –1); m = y + 10 = (x + 1) y + 1 = (x + 10) y – 1 = (x – 10) y – 1 = (x + 10) write an equation for the line that is parallel to the given line and that passes through the given point. y = x – 10; (–6, –29) y = x + 14 y = x – 14 y = x – 14 y = x mc

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