1. classify the situation as direct or inverse variation. super shine car wash charges $13 per wash. direct variation or inverse variation 2.classify the situation as direct or inverse variation. super shine car wash charges $13 per wash. direct variation or inverse variation 3. xy = 8 direct variation or inverse variation 4. y/x = 2.5 direct variation or inverse variation 5.classify the situation as direct or inverse variation. the longer you drive, the greater the distance you travel direct variation or inverse variation

1. and 2. Direct variation

3. Inverse variation

4. Direct variation

5. Direct variation

Step-by-step explanation:

In direct variation if one variable increase the other one also increase

In inverse variation if one variable increase the other one decrease

1. and 2. Direct variation. As the number of washes increase the cost increase.

3.Inverse variation. If x increase, y has to decrease so that their multiplication remains the same

4. Direct variation. If y increase, x has to increase so that their division remains the same

5. Direct variation. As you spend more time travelling the distance you travel increase

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)