Leah is solving the equation using properties of exponents? 2^2x-3=(1/6)^3x+9

HERE IS HOW TO SOLVE:

Simplify {2}^{2}2

​2

​​  to 44

4x-3={(\frac{1}{6})}^{3}x+94x−3=(

​6

​

​1

​​ )

​3

​​ x+9

2 Use Division Distributive Property: {(\frac{x}{y})}^{a}=\frac{{x}^{a}}{{y}^{a}}(

​y

​

​x

​​ )

​a

​​ =

​y

​a

​​  

​

​x

​a

​​  

​​  

4x-3=\frac{1}{{6}^{3}}x+94x−3=

​6

​3

​​  

​

​1

​​ x+9

3 Simplify {6}^{3}6

​3

​​  to 216216

4x-3=\frac{1}{216}x+94x−3=

​216

​

​1

​​ x+9

4 Simplify \frac{1}{216}x

​216

​

​1

​​ x to \frac{x}{216}

​216

​

​x

​​  

4x-3=\frac{x}{216}+94x−3=

​216

​

​x

​​ +9

5 Multiply both sides by 216216

864x-648=x+1944864x−648=x+1944

6 Add 648648 to both sides

864x=x+1944+648864x=x+1944+648

7 Simplify x+1944+648x+1944+648 to x+2592x+2592

864x=x+2592864x=x+2592

8 Subtract xx from both sides

864x-x=2592864x−x=2592

9 Simplify 864x-x864x−x to 863x863x

863x=2592863x=2592

10 Divide both sides by 863863

ANSWER: x= 2592 over 863

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

the answer is  

d.

121π mi^2

hope you got it chief