The length of the rectangle is twice its width. write and solve a system of linear equations to find the length l and width w of the rectangle (perimeter=36)

1)  L = Length,  W = Width, perimeter = 36

then

2L+2W =36

L = 2W

of the equation 1 , find  W

2L+2W = 36⇒2L=36-2W⇒L= 36-2W/2⇒L= 18-W

Now substitute it value with the equation 2

18-W = 2W⇒18 =2W+W⇒18= 3W⇒W= 18/3 = 6, L = 18-6 = 12

NOW SUBSTITUTE THE VALUES IN THE EQUATION 1

2* 12+ 2*6 = 36 , IT IS FULFILLED

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

125 yards

step-by-step explanation:

i take 75 plus 50.