The length of the rectangle is twice its width. write and solve a system of linear equations to find the length l and width w of the rectangle (perimeter=36)

The length is equal to 12 and the width is equal to 6.

Step-by-step explanation:

In order to find the values here, we start by setting the width equal to x. Now knowing this, we know that the length is twice that long. Therefore, the length would be equal to 2x. Now we can use the perimeter formula to solve the equation.

2L + 2W = P

2(2x) + 2(x) = P

4x + 2x = 36

6x = 36

x = 6

Now with the given value for x, we can tell that the width is 6 and then we multiply it by 2 to get the length value (12).

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a