The line r represents f(x)= x-4/3. therefore, the line that represents f^-1 is and f^-1 (x) =

f^-1 is line P and f^-1 (x) = 3x +4

Step-by-step explanation:

Same reasons as Ikarus

Answer

f^-1(x) = 3x + 4

Step by step explanation

Here we have to find the inverse function of f(x)

f(x) = (x - 4)/3

We can represents f(x) = y

y = (x - 4)/3

To find the inverse function replace "x" by "y" and "y" by "x" as follows

x = (y - 4)/3

Now write the y interms of x.

Multiply by both sides by 3, we get

3x = y - 4

Add 4 on both sides, we get

3x + 4 = y - 4 + 4

3x + 4 = y

Therefore the inverse function f^-1(x) = 3x + 4

Thank you.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)