What is the value for y? enter your answer in the box. y = an isosceles triangle a b c with horizontal base b c and vertex a is above the base. side a c and c b are labeled with single tick mark. all the three angles are labeled. base angles c a b is labeled as 50 degrees and angle c b a is labeled as 2x degrees. the angle a c b is labeled left parenthesis 5 y plus 10 right parenthesis degrees.

x = 25

y = 14

Explanation:

The described scenario can be represented using the attached triangle.

1- getting the value of x:

We know that ΔABC is an isosceles triangle with AC = BC

This means that:

∠CAB = ∠CBA

We know that ∠CAB = 50° and ∠CBA = 2x°

Equating the two angles, we get:

50 = 2x .................> Divide both sides by 2

x = 25

2- getting the value of y:

We know that the sum of the internal angles of a triangle is 180°

This means that:

∠ABC + ∠CAB + ∠ACB = 180°

We have:

∠ABC = 2x = 50°

∠ACB = 5y + 10

∠CAB = 50°

Now, we substitute to get the value of y as follows:

50 + 50 + 5y + 10 = 180

110 + 5y = 180

5y = 180 - 110

5y = 70 .............> Divide both sides by 5

y = 14

Hope this helps :)

i think asking google will you get the answer to that question

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4