If x2 + mx + m is a perfect-square trinomial, which equation must be true? x2 + mx + m = (x – 1)2 x2 + mx + m = (x + 1)2 x2 + mx + m = (x + 2)2 x2 + mx + m = (x + 4)2

for to be a perfect square trinomial,

or

thereore,

4m=m²

m²-4m=0

(m)(m-4)=0

m=0 and m-4=0

m=0 and m=4

so you could have

x²+0x+0=(x-0)²

or

x²+4x+4=(x+2)²

answer is 3rd optio, (x+2)²

answer: add the !

step-by-step explanation: then we will answer