Twenty years ago a small town in texas had a population of 10,000. the population has increased 8% each year since then. what is the growth factor that would be used to solve this problem? a. the growth factor would be 8 b. the growth factor would be 0.08 c. the growth factor would be 1.08 d. the growth factor would be 0.92

     c. The growth factor would be 1.08  .

Step-by-step explanation:

The exponential growth model is given by :-

, where A is the initial value, r is the rate of growth and n is the time period.

Also, the growth factor = 1+r

Given: The rate of increase of population = 8%=0.08

Now, the growth factor =

Therefore, the growth factor would be 1.08.

i think the answer is d im not sure

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)