Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. write an equation in slope-intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation.

1) Given equation: .

Slope of the given equation = .

Parallel lines have equal slopes.

Therefore, slope of parallel line is also .

Given point (2,-1).

Applying point slope form y-y1 = m(x-x1)

y - (-1) =(x-2)

y+1 =  

Subtracting 1 from both sides, we get

.

2) Given equation x=-3.

The given line is a vertical line.

Therefore, parallel line would also be a vertical line.

For the given point (4,2) we would have equation for vertical line x = 4.

3) Given equation: .

Slope of the given line is : .

Slope of perpendicular line is negative reciprocal.

Therefore, slope of perpendicular line  = -2.

Given point (-2,3).

Applying point-slope form, we get

y-3 = -2(x-(-2))

y -3 = -2 (x+2)

y -3 = -2x -4 .

Adding 3 on both sides, we get

y = -2x -1.

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.

i think is g(1)=-1.

hope that i can