Abc point d is the midpoint of ab , point e is the midpoint of bc , and point f is the midpoint of be . find area of △abc, if adcf= 63 cm2

168 cm²

... ADBC = (1/2)AABC because DC is a median of ∆ABC.

... ADEC = ADEB = (1/2)ADBC because DE is a median of ∆BDC.

... ADEF = (1/2)ADEB because DF is a median of ∆BDE.

The given area is the sum of two of the areas described above:

... ADCF = ADEC + ADEF

... ADCF = (1/2)ABDC +(1/2)ADEB . . . . substitute from above

... = (1/2)(1/2)AABC + (1/2)(1/2)(1/2)AABC . . . . more substitution

... = (3/8)AABC

Multiplying by 8/3 gives ...

... AABC = (8/3)ADCF = (8/3)×(63 cm²)

... AABC = 168 cm²

4sqrt5

step-by-step explanation:

the base has dimensions of 8 x 4, so the diagonal is 64 + 16 square rooted or 4sqrt5.