The mean ages with standard deviations of four swim teams at a swim club are given below. team mean standard deviation stars 16 4.1 dolphins 18 1.5 giants 14 0.3 mackerels 15 2.3 which statement is most likely to be true? the ages of the mackerels are the most dispersed from the team’s mean. the ages of the stars are the most dispersed from the team’s mean. the ages of the dolphins are the most dispersed from the team’s mean. the ages of the giants are the most dispersed from the team’s mean

Solution: We are given the below table of information:

Team                    Mean                  Standard deviation

Stars                        16                                4.1

Dolphins                 18                                 1.5

Giants                      14                                0.3

Mackerels                15                                2.3

The correct answer is:

The ages of the Stars are the most dispersed from the team’s mean.

Explanation: Standard deviation is a measure of dispersion that tells us how our number's are dispersed from the mean. More the standard deviation means more the dispersion of values from the mean.

Looking at the standard deviations column we clearly see the Stars have the highest standard deviation among the given four teams. Therefore, the ages of stars are most dispersed from the team's mean

B on edg

Step-by-step explanation:

the answer is 510

step-by-step explanation:

15 • 13 = 195

15 • 12 = 180

15 • 5 = 75

12 • 5 = 60

195 + 180 = 375

375 + 75 = 450

450 + 60 = 510