Find an equation for the perpendicular bisector of the line segment whose endpoints are (-9,-8) and (7,-4

equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)

Perpendicular bisector lies at the midpoint of a line

Lets find mid point of  (-9,-8) and (7,-4)

midpoint formula is

midpoint is (-1, -6)

Now find the slope of the given line

(-9,-8) and (7,-4)

Slope of perpendicular line is negative reciprocal of slope of given line

So slope of perpendicular line is -4

slope = -4  and midpoint is (-1,-6)

y - y1 = m(x-x1)

y - (-6) = -4(x-(-1))

y + 6 = -4(x+1)

y + 6 = -4x -4

Subtract 6 on both sides

y = -4x -4-6

y= -4x -10

equation for the perpendicular Bisector y = -4x - 10

33/100 is what i got