Find the value of k so that the graph of 19y - kx and the line containing the points (5,-8) and (2,4) are parallel

-4/19

Explanation:

Here, we will use point-slop equation of the line to find the value of k

m = (y2 - y1)/(x2 - x1)

we can find the value of m using the points on the second line containing (5, -8) and (2,4)

               m  = (4 - (-8))/(2 - 5) = 12/(-3) = -4 (i)

we will convert the first line equation into sloper intercept form

                                       y = mx + c

                                       0 = 19y - kx

                                        19y = kx

                                         y = kx/19

                                         y = (k/19)*x

Here the m = k/19 and c = 0

Because the lines are parallel so their slop m would must be same.

Inserting the value of m of second line from the line (i)

                                   -4 = k/19

                                    k = -4/19

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

answer: i can’t tell you that

step-by-step explanation: