Find the area of the region bounded by the y-axis, the line y=6, and the line y = 1/2.

Solution:

As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.

We consider a line , one dimensional  if it's thickness is negligible.

So, Line is  two dimensional if it's thickness is not negligible becomes a quadrilateral.

So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and  y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.