The width of the figure below is 5 units. the perimeter of the figure is 18 units. what is the length of the figure in units?

if the figures perimeter is 18 units, and the width of the figure is 5 units. I am guessing the figure is a rectangle

where the width is 5 units, and 2 of the sides have 2 be the same 2 be a rectangle, than the width on each side is 10 units all together

18-10= 8

if the figure is a rectangle then that means there are 2 sides left of equal length so if we divide our current number (8) by 2 then we will have the length of each side (4)

8 divided by 2= 4

width= 5

length= 4

answer is 67%

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2