Members of the service club at rebecca's school must spend a minimum of 20 hours doing volunteer work each semester. the number of hours spent volunteering at school activities can be no more than twice the number of hours spent volunteering outside of school. when x represents the number of hours spent volunteering in school and y represents the number of hours spent volunteering outside of school, this situation can be modeled by a system of inequalities. which ordered pairs represent solutions to the system? (12,5) (0,22) (10,10) (15,6) (7,11) (8,16)

Let x represents the number of hours spent volunteering in school and y represents the number of hours spent volunteering outside of school.

1. Since each member must spend at least 20 hours doing volunteer work each semester, then

x+y≥20.

2. Since the number (x) of hours spent volunteering at school activities can be no more than twice the number (y) of hours spent volunteering outside of school, then

x≤2y.

You get a sytem of two inequalities:

Consider all pairs:

1. (12.5): 12 is not ≤ 2·5=10 -false;

2. (0,22): 0+22≥20 and 0≤2·22=44 - true;

3. (10,10): 10+10≥20 and 10≤2·10=20 - true;

4. (15,6): 15 is not ≤ 2·6=12 -false;

5. (7,11): 7+11=18 is not ≥ 20 -false;

6. (8,16): 8+16=24≥20 and 8≤2·16=32 - true.

correct choices are 2, 3 and 6.

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i