John goodman weighs 250 pounds, so he decides to go on a diet. at the end of the first week, he weighs 240. then at the end of the second week, he weighs 230. fill in the blanks of the arithmetic formula [ a(n) = d + a1(n – 1) ] for this scenario. a(n) = + (n – 1 )

Answer

nth term of an AP of first term 250 and common difference -10 can be written as,

A(n) = 250 + (n-1)(-10)

Explanation

This is an example of Arithmetic progression(AP). Le a be the first term, d be the common difference, then nth term is given by

A(n) = a + (n-1)d  

Step 1

John Goodman weighs 250 pounds, so he decides to go on a diet.  

So we can write 'a' = 250

Step 2

At the end of the first week, he weighs 240.

Then at the end of the second week, he weighs 230.  

Fro this we get,  d = 40 -250 = -10 = 230 - 240

Step 3

Therefore using formula A(n) = a + (n-1)d  

A(n) = 250 + (n-1)(-10)

i got 86 for this

hope this !

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