After reaching a high temperature of 25°c at 2: 00 p. m., the temperature drops at a rate of 2°c per hour. what is the temperature at 5: 00 p. m.?

19 degrees C

5-2

3*2

25-6

The temperature at 5:00 PM would be 19*C.

Step-by-step explanation:

First, subtract the original time from the new time:

5 - 2 = 3

Find the amount of C that would go down in 3 hours:

3 * 2 = 6

Subtract the 6 C from the original temperature of 25 C:

25 - 6 = 19

the first dot plot best represents the data

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. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: