If f(3)=191.5 when r =0.03 for the function f(t)=pe^rt, then what is the approximate value of p? a. 175 b. 78 c. 210 d. 471

The correct option is A.

Step-by-step explanation:

The given function is

It is given that f(3)=191.5 and r =0.03.

Substitute t=3 and r=0.03 in the given function.

The value of F(3)=191.5. Put F(3)=191.5 in the above equation.

Divide both sides by 1.0942.

The approximate value of p is 175. Therefore the correct option is A.

true !

step-by-step explanation: