The cost of 12 oranges and 6 apples is $5.38 eight oranges and 5 apples cost $3.68 find the cost of each

Let the oranges cost = x

Let the apples cost = y

According to given conditions, equation becomes:

.... (1)

   .....(2)

Multiplying equation (1) by 8 and equation (2) by 12 to get y

96x+48y=43.04   .... (3)

96x+60y=44.16 .... (4)

Now subtracting both equations we get,

12y = 1.12

y = 0.093

Hence, cost of 1 apple = $0.093

As 12x+6y=5.38

12x+6(0.093)=5.38

12x=4.822

x = 0.40

Hence, cost of 1 orange = $0.40

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b