Kyle and michael run a lap around a track. kyle gets a 50 meter head start and runs 3 meters per second. michael runs at a speed of 4 meters per second. how long will it take for michael to reach kyle

First, you need to put both equations in slope intercept form

Kyle: y=3x+50, because he runs 3 meters/second and he gets a 50 meter head start

Michael: y=4x

I think the answer would be 50 seconds

hope this helps

50 seconds

Step-by-step explanation:

Let x be the distance ( in meters ) from kyle to the point where they meet.

Since,

For kyle,

Distance = x,

Speed = 3 m/s

So, time taken by Kyle =

Now, for Michael,

Distance = (x + 50) ( Because Kyle is 50 meters ahead of Michael )

Speed = 4 m/s

So, time taken by Michael =

When they meet each other,

Hence, the time after which they meet = = 50 seconds

im pretty sure its

(8,15)

step-by-step explanation:

hi there!

question 1 answer: p/q can be terminating when q = 5^m * 2^n

question 2 answer: -1 and -1

question 3 answer: -4

question 4 answer: 5/12

hope this : )