Write an equation of a line that is perpendicular to x=3 and passes through (0,-4)

The equation of a vertical line: x = a (a - any real number).

The line perpendicular to x = 3 is a horizontal line.

The equation of horizontal line: y = b (b - any real number).

The horizontal line passes through (0, -4) → x = 0 and y = -4.

Therefore your answer is

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4