Does anyone know how to do #4 plz !

The area of the circular ends of the cylinder.

Step-by-step explanation:

The total surface area of a right circular cylinder is

... total area = area of circular ends + lateral surface area

The lateral surface area can be considered to be a rectangle whose length is the circumference of the cylinder and whose width is the height of the cylinder. For a cylinder of radius r and height h, this is described by the product ...

... lateral surface area = 2πrh

The area of the (congruent) circular ends is twice the area of one of the ends. That area is the area of a circle of radius r, so is described by ...

... area of one circular end = πr²

Then ...

... area of circular ends = 2πr²

and the total area of the cylinder is ...

... total area = 2πr² + 2πrh . . . . matches the formula in your problem statement

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: