The length of a rectangle is 8 cm more than 3 times its width. the perimeter of the rectangle is 64 cm. show the equation that would be used to find the dimensions of the rectangle. let w = the width. then 3w = length + 8. so the equation is 64 = 2(3w – 8) + 2w. let w = the width. then 3w + 8 = length. so the equation is 64 = 2(3w + 8) + 2w. 64 = 2(3w + 8) + 2w let w = the width. then 3(w + 8) = length. so the equation is 64 = 2(3(w + 8)) + 2w. let w = the width. then 3w + 8 = length. so the equation is 64 = (3w + 8) w.

The correct answer should be B, Let w = the with. the 3w + 8 = length. so the equation is 64 = 2(3w + 8) + 2w. 64 = 2(3w + 8) + 2w

Step-by-step explanation:

Perimeter = Length+Length+Width+Width

The Length (L) is +8 cm bigger then the Width (w) *3

L = 3W+8

64 = (3W+8)+(3W+8)+W+W

64 = 2(3W+8)+2W

hey seth! : )

i’m not 100% sure, but i think it’s b

hope this ya : p

miss u!

- nicole

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540