Alocal phone company charges a monthly fee of $34.99 plus $.05 for each minute of long distance calls. parts of minutes are rounded up to the next whole minute. find the minimum and maximum long-distance minutes for customers whose monthly bill is at least $53.24 but no more than $132.00. a. at least 2, no more than 3 b. at least 365, no more than 1,940 c. at least 365, no more than 1,941 d. at least 1,065, no more than 2,640

53.24-34.99=18.25

$1 will buy 20 minutes of long distance calling

x$18.25 = 365 minutes @ $34.99

$132-$34.99=$97.01

20x97=1,940 minutes

minimum=365 minutes

maximum=1,940 minutes

Hope this helps.

(B) at least 365, no more than 1,940

Explanation:

The customers whose bill is $53.24, are charged $53.24-$34.99 for their minutes: $18.25 / $0.05 per min = 365 minutes, so that is the minimum of minutes.

When the bill reaches $132, the actual minutes charge is $132-$34.99=$97.01.

The corresponding number of minutes is $97.01/$0.05 per min = 1940.2 minutes. The maximum, however, must be 1940 minutes because if we rounded up to 1941, the charges would have been $97.05, which would exceed the given amount of $132.

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i