Y+2=1/3 x+3 identifty the point and the slope

point slope form

y-y1 = m(x-x1)

y- (-2) = 1/3 (x- -9)   check y+2 = 1/3(x+9)  y+2 = 1/3x +3

point (-2,-9) slope 1/3

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i