Which statement is true about the extreme value of the given quadratic equation? y=-3x2+12x-33a.  the equation has a minimum value with a  y-coordinate  of -27.b.  the equation has a maximum value with a  y-coordinate  of -21.c.  the equation has a minimum value with a  y-coordinate  of -21.d.  the equation has a maximum value with a  y-coordinate  of -27.

Given quadratic equation : .

A quadratic equation represents a parabola.

We have leading coefficient is -3, a negative number.

So, it would be a downward parabola and it would have it's vertex point on the top on the parabola.

So, it would obviously have a maximum value.

Let us find the x-coordinate of the parabola first and then y-coordinate of the parabola.

x = -b/2a = -12/2(-3) = -12/-6 = 2.

Plugging x=in given equation, we get

y=-3(2)^2+12(2)-33 = -3(4) +24 -33

  = -12 +24 -33 = -21.

Therefore, maximum value is -21.

Therefore, correct option is :

step-by-step explanation:

my butt

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.