Graph the line using a point and a slope. write the equation of each line. f a line that passes through the point (–1, –4) and whose slope is –2.

Dos rectas cuyas pendientes son m1 y m2, son perpendiculares si y sólo si m1m2 =-1

with a point and the slope you can find the equation

y-y1=m(x-x1)

as the point is given (-1,-4) then substitute it in the equation

y-(-4)= -2[(x-(-1)]⇒y+4= -2x-2⇒y=-2x-2-4⇒y=-2x-6 and this is the equation of the line that must be graphed

second step)

graph the equation y =- 2x-6, with the points of intersection are for  x = 0, y = -2(0)-6= -6 , the point is ( 0,-6) and the other point is for y = 0  

0= -2x-6,  2x= -6, x = -6/ 2 = -3, the other point is (-3,0) then the graph is the following,   you can see in it the points of intersection

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point