There are 80 guards and 32 forwards in ben's basketball league. ben must include all players on a team and he wants each team to have the same number of guards and the same number of forwards. if ben creates the greatest number of teams possible, how many forwards will be on each team?

Step-by-step explanation:

The greatest common factor between 32 and 80 is 16 not 8.  

32 (forwards) / 16 (teams) = 2 forwards on each team.

80 (guards) / 16 (teams) = 5 guards on each team.

 Number of forwards = 32 ÷ 16 = 2    

Step-by-step explanation:

For finding the same number of guards and same number of forwards for each time we should first calculate highest common factor (HCF) of 80 guards and 32 forwards.

Thus, finding factors of 80 and 32:

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

Thus, HCF of 80 and 32 = 2 × 2 × 2 × 2 = 16.

Hence, Number of guards = 80 ÷ 16 = 5

And, Number of forwards = 32 ÷ 16 = 2.

answer:   rlly

step-by-step explanation:

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6