Two cards are chosen from a standard deck of 52 playing cards without replacement. what is the probability that both cards are fours? a 1/221 b 30/221 c 1/169 d 3/676

There are 4 fours in a deck of cards.

Picking a four first would be 4/52 which reduces to 1/13

After the first pick there are 51 cards left with 3 fours.

Picking the second four would be 3/51, which reduces to 1/17.

The probability of picking 2 fours = 1/13 x 1/17 = 1/221

The answer is A.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right