Find the quotient of 4x^3+x^2-2x+3/x+2

4x^2 - 7x + 12 - 21/(x + 2)

Step-by-step explanation:

                             4x^2 - 7x + 12

                 x + 2  | 4x^3 + x^2 - 2x + 3

                             4x^3 + 8x^2

                                       -7x^2 - 2x

                                       -7x^2 - 14x

                                                  12x +3

                                                  12x + 24

                                                          -21

4x^2 - 7x + 12 - 21/(x + 2)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐