Ineed ! what is the equation of the line perpendicular to 3x + y = -8 that passes through (-3,1) ? write your answer in slope-intercept form. show your work.

y = x + 2

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 3x + y = - 8 into this form

subtract 3x from both sides

y = - 3x - 8 ← in slope-intercept form

with slope m = - 3

given a line with slope m then the slope of a line perpendicular to it is

perpendicular slope = - =

y = x + c is the partial equation of the perpendicular

to find c substitute (- 3, 1 ) into the partial equation

1 = - 1 + c ⇒ c = 2

y = x + 2 ← in slope-intercept form

its not b

step-by-step explanation:

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !