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Mathematics, 03.07.2019 05:00 juli8350

Describe and correct the error to solving the equation. a there is an extraneous solution of  x=βˆ’4x=βˆ’4, so the solution is  x=5x=5.b there is an extraneous solution of  x=5x=5, so the solution is  x=βˆ’4x=βˆ’4.cthe absolute value cannot be negative, so there is no solution. d the absolute value cannot be negative, so one solution must be extraneous.

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Describe and correct the error to solving the equation. a there is an extraneous solution of  x...
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