What is the solution of |2x+3|=3x+5?

x= -8 / 5

Step-by-step explanation:

There are 2 equations, since |x|=x when x>0 and  |x|=-x when x<0

So, the first equation is

1. 2x+3=3x+5 when (x>0)

2. -2x-3=3x+5 when (x<0)

Lets solve the first equation by moving terms, on one side x terms, and on the other, free terms. Thus we have the following result

x=-2, which is a contradiction since we stated earlier that x>0, so this leads us to claim that eq.1 has no solutions

Now lest do something similar with eq.2. We get the following result. x=-8/5

This results satisfies the condition stated earlier, that x<0

So, the system |2x+3|=3x+5 has only one solution, x= -8/5

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms