Which equation has the solution set x= {2,3}? a.2/3x=0 b.(x-2)(x-3)=0 c.(x+2)(x+3)=0 d.(2x+3)^2=0

B

(x - 2)(x - 3) = 0

To solve equate each of the factors to zero and solve for x

x - 2 = 0 ⇒ x = 2

x - 3 = 0 ⇒ x = 3

solution set is x∈ [2, 3]

note that (x + 2)(x + 3) = 0 has solution set x ∈[- 2, - 3]

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: