Why is the product of two rational numbers always rational? select from the drop-down menus to correctly complete the proof. let a/b and c/d represent two rational numbers. this means a, b, c, and d are (integers, irrational numbers) , and b and d are not 0. the product of the numbers is ac/bd , where bd is not 0. both ac and bd are (integers, irrational numbers) , and bd is not 0. because ac/bd is the ratio of two (integers, irrational numbers) , the product is a rational number.

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Let a/b and c/d represent two rational numbers. This means a, b, c,and d are INTEGERS , and b and d are not 0. The product of the numbers is ac/bd , where bd is not 0. Both ac and bd are INTEGERS , and bd is not 0. Because ac/bd is the ratio of two INTEGERS, the product is a rational number.

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5

i use my brain for prombles like this maybe you could try it

step-by-step explanation: