Given f'(x) = (x-4)(4-2x), find the x-coordinate for relative maximum on the graph of f(x)

The coordinate of the relative maximum is x=4.

Step-by-step explanation:

Given that the derivative of the function is , the maxima and minima or the critical points can be found where that is:

The solutions to this equation are and

Now, if the second derivative for a function  is negative at a critical point, then the critical point is the relative maximum.

Therefore we want to see at which of the two critical points is negative. The second derivative is:

Now is , and is , therefore we deduce that the relative maxium is located at , because there the second derivative is negative.

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step-by-step explanation:

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer