Give the slope-intercept form of the equation of the line that is perpendicular to –7x + 5y = 12 and contains p(–7, 4).select an answery  =  x  y  =  x  y  – 7 =  (x  + 4)y  – 4 =  (x  + 7)

y = - x - 1

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange - 7x + 5y = 12 into this form

add 7x to both sides

5y = 7x + 12 ( divide all terms by 5 )

y = x + ← in slope- intercept form

with slope m =

given a line with slope m then the slope of a line perpendicular to it is

perpendicular slope = - = -

The partial equation of the perpendicular line is

y = - x + c

to find c substitute (- 7, 4 ) into the partial equation

4 = 5 + c ⇒ c = 4 - 5 = - 1

y = - x - 1 ← in slope- intercept form

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: