From points a and b, the distance between which is 1020 mi, two trains left simultaneously towards each other. the speed of one train was 10 mph greater than the speed of the other one. in 5 hours the trains had not met yet and were 170 mi apart. find the speed of the trains. plz just give me the !

From points A and B, the distance between which is 1020 mi

The speed of one train was 10 mph greater than the speed of the other one

Let the Speed of first train is x

Speed of second train is x+ 10

Time = 5 hours

Distance = speed * time

Distance traveled by first train = x * 5= 5x

Distance traveled by second  train = (x+10) * 5= 5x + 50

the trains had not met yet and were 170 mi apart.

the distance between A  and B is 1020 mi, Distance traveled by two trains = 1020 - 170 = 850 miles

Distance traveled by first train + second train = 850

5x + 5x + 50 = 850

10x + 50 = 850

Subtract both sides by 50

10x = 800

x= 80

Speed of first train is 80 miles per hour

Speed of second train is 90 miles per hour

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!

$79500

step-by-step explanation: