Find the distance between the points: (–6, 7) and (–1, –5). in your final answer, include the formula and calculations that you used to find the distance.

The distance between the points (-6,7) and (-1,-5) is 13 units.

Solution:

P1=(-6,7)=(x1,y1)→x1=-6, y1=7

P2=(-1,-5)=(x2,y2)→x2=-1,y2=-5

Distance between points P1 and P2: d=?

d=sqrt [ (x2-x1)^2 + (y2-y1)^2 ]

Replacing the knwon values:

d=sqrt [ (-1-(-6))^2 + (-5-7)^2 ]

d=sqrt [ (-1+6)^2 + (-12)^2 ]

d=sqrt [ (5)^2 + 144 ]

d=sqrt [ 25 + 144 ]

d=sqrt [ 169 ]

d=13

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

the answer is d on edge

step-by-step explanation: