5. factor the expression. 6x2 + 5x + 1 a)(3x + 1)(2x – 1) b)(3x – 1)(2x – 1) c)(3x – 1)(2x + 1) d)(3x + 1)(2x + 1)

The factored version of the equation 6x^2 + 5x + 1 is equal to (3x+1)(2x+1).

Step-by-step explanation:

Here is the reason why that equation is correct:

Use the FOIL method for each factored equation to see if it equals 6x^2 + 5x + 1.

(3x + 1)(2x - 1)

3x * 2x = 6x^2.

3x * -1 = -3x.

1 * 2x = 2x.

1 * -1 = -1.

6x^2 - x - 1.

(3x - 1)(2x - 1)

3x * 2x = 6x^2.

3x * -1 = -3x.

-1 * 2x = -2x.

-1 * -1 = 1.

6x^2 - 5x + 1.

(3x -  1)(2x + 1)

3x * 2x = 6x^2.

3x * 1 = 3x.

-1 * 2x = -2x.

-1 * 1 = -1.

6x^2 + x - 1.

(3x + 1)(2x + 1)

3x * 2x = 6x^2.

3x * 1 = 3x.

1 * 2x = 2x.

1 * 1 = 1.

6x^2 + 5x + 1.

D contains the only factored expression that equals 6x^2 + 5x + 1 as a result using the FOIL method.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.