In a country x all markers are red or blue. in a box in country x there are 9 markers. i look at a random marker in the box and see that it is blue. what is the probability that in the box there are 1 red and 8 blue markers

Answer-

The probability that in the box there are 1 red and 8 blue markers is 0.111 or 11.1%

Solution-

In the box all markers are red or blue. There are total of 9 markers.

So the number of possible combination number of red or blue marker is,

As at the random drawn, there was a Blue marker, so the condition of (9,0) i.e 9 Red marker and 0 Blue marker is not a case.

So the sample space becomes,

Let us assume that E is the event that in the box there are 1 red and 8 blue markers. So

The probability that in the box there are 1 red and 8 blue markers is,

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?