If the equation below is solved by graphing, which statement is true? log(6x+10)=log1/2x the curves intersect at approximately x = 0.46. the curves intersect at approximately x = 0.75. the curves intersect at approximately x = 1.11. the curves intersect at approximately x = 3.07.

.46

Step-by-step explanation:

If you graph the function, you can see where the two logs intersects. View the image I have attached.

If the equation log(6x+10)=log(1/2) x is solved by graphing, the curves intersect at approximately x=0.46

Step-by-step explanation:

Equation

log(6x+10)=log(1/2) x

We must graph two functions:

f(x)=log(6x+10) and

g(x)=log(1/2) x→g(x)=log0.5 x

If we graph these two equation the point of intersection is approximately (0.464, 1.107)=(x,y)

x=0.464→x=0.46

y=1.107→y=1.11

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1