Given f(x)=x^2-5 and g(x)=20-x find (f-g)(2)

f-g = x^2-5 - (20-x)

f-g = x^2 -5-20+x

f-g = x^2 +x-25

f-g(2) = 2^2 +2 -25

      = 4+2-25

     = -19

i belive those are the ones that are under 90 degreese.

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)