The table shows the distance that two trains are from center station at various times of the day. miles from center station time of day train 1 train 2 11: 30 13 7 12: 00 31 27 12: 45 58 57 how do the speeds of the trains compare? train 1 is traveling 1 mile per hour faster than train 2. train 1 is traveling 6 miles per hour faster than train 2. train 2 is traveling 4 miles per hour faster than train 1. train 2 is traveling 5 miles per hour faster than train 1.

A ratio of minutes to distance can help to solve this

Train 1: (31-13)/(12-11.5)

Train 1: 18/0.5

Train 2: (27-7)/0.5

Train 2: 20/0.5

So here we have speeds of

Train 1: 36mph

Train 2:40mph

We can check this again with the second set.

Train 1: (58-31)/0.75

Train 1: 27/0.75

Train 2: (57-27)/0.75

Train 2: 30/0.75

Convert this and we have

Train 1: 36mph

Train 2: 40mph

Now that this is confirmed we see that Train 2 is traveling 4mph faster than Train 1.

The answer is C: Train 2 is traveling 4 miles per hour faster than train 1.

Step-by-step explanation:

I took the test

1,589.63 in.^3

step-by-step explanation:

i hope this you : d

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl