Suppose a triangle has two sides of length 32 and 35, and that the angle between these two sides is 120°. what is the length of the third side of the triangle? a. 58.04b. 47.43c. 33.60d. 53

A. 58.04°

Step-by-step explanation:

Let the sides of the triangle be A , B  and C.

A = 32

B = 35

C = what we don't know.

The opposite angle to C is 120° and its just denoted as ∡C

The formula to find C² = A² + B² - 2ABcos∡C

C² = 32² + 35² - 2(32)(35)cos120°

C² = 1024 + 1225 - 2240cos120°

C² = 3369

C = ≅ 58.04°

452,489 to the nearest thousand is 452,000

step-by-step explanation:

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