The speed of a freight train is 14 km slower than the speed of a passenger train the freight train travels 330 km in the same time that it takes the passenger train to travel 400 km find the speed of the freight trian

Freight train DATA:

rate = x-14 kmh; distance = 330 km ;time = d/r = 330/(x-14) hrs

Passenger Train DATA:

rate = x km/h ; distance 400 km ; time = d/r = 400/x hrs

Equation:

time = time

330/(x-14) = 400/x

330x = 400x - 14*400

70x = 14*400

x = 80 km/h (speed of the passenger train)

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x-14 = 66 km/h (speed of the freight train)

a

Step-by-step explanation:sorry if im wrong

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.