What is the equation parallel to 3x+2y=8 that goes through the point 2, -4

The equation of the line would be y = -3/2x - 1

Step-by-step explanation:

In order to find this, we first need to find the slope of the original line. We do this by solving for y.

3x + 2y = 8

2y = -3x + 8

y = -3/2x + 4

Since we know parallel lines have the same slope, we know our new line has a slope of -3/2. We can now use that along with the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - -4 = -3/2(x - 2)

y + 4 = -3/2x + 3

y = -3/2x - 1

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

42

step-by-step explanation: