Write an equation in slope intercept form of a line that is perpendicular to the line y=6x+1 and contains the point (12,-1). start with the line in point slope form. show work! plz !

The equation of the line would be y = -1/6x + 1

Step-by-step explanation:

In order to find this, we first need to set the slope. Since the original slope is 6, we know the new slope to be -1/6. This is because perpendicular slopes have opposite and reciprocal slopes. So, we put this and the point into point-slope form.

y - y1 = m(x - x1)

y - -1 = -1/6( x -12)

y + 1 = -1/6x + 2

y = -1/6x + 1